methods - Java: Parameter list without comma -


i came across method parameter list parameter not separated comma , no declaration of variable type: 

public int comparewith(choice anotherchoice){

later these parameters called without further declaration inside body in if-else statement in combination method:

if ((this.type == 0)&&(anotherchoice.gettype() == 1)){         return -1;

this brief summary of entire class: 

public class choice {  private int type;    public choice(int type) {     //initialize "type" instance varialble     this.type = type; }    public int gettype() {     return type; }   public int comparewith(choice anotherchoice) {    choice choice1 = new choice(0);    choice choice2 = new choice(1);    if ((this.type == 0)&&(anotherchoice.gettype() == 1)){         return -1;

the program goes on. don't link between anotherchoice, gettype() , choice2. task in online course , program works intended, don't know why.

i'm guessing you're new programming, i'll give quick explanation of what's going on. if i've missed point of question entirely, i'm sorry.

this line:

public int comparewith(choice anotherchoice){

is part of choice object. takes choice object , compares itself. ...or @ least, that's expect. code provided:

public int comparewith(choice anotherchoice) {    choice choice1 = new choice(0);    choice choice2 = new choice(1);    if ((this.type == 0)&&(anotherchoice.gettype() == 1)){         return -1;

is incomplete , have no idea choice1 , choice2 supposed doing. code expect see more like

public int comparewith(choice anotherchoice) {    if (this.type == anotherchoice.gettype())         return 0;    return -1; }

or that.

does help?


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