linux - Not getting right output if i execute command via ssh -


the output of following command 

sudo find / -xdev -type f -size +100000 -name "*.log" -exec gzip -v {} \; 2>&1 | awk '{print $6}'

give me

/opt/testing3/cat1.log.gz /opt/testing3/cat2.log.gz /opt/testing3/cat3.log.gz /opt/testing3/cat4.log.gz /opt/testing3/cat5.log.gz /opt/testing3/cat6.log.gz /opt/testing3/cat7.log.gz

however if via ssh gives me:

 ssh user@hostname "sudo find / -xdev -type f -size +100000 -name \"*.log\" -exec gzip -v {} \; 2>&1 | awk '{print $6}'"

results in

/opt/testing3/cat1.log:  95.4% -- replaced /opt/testing3/cat1.log.gz /opt/testing3/cat2.log:  95.4% -- replaced /opt/testing3/cat2.log.gz /opt/testing3/cat3.log:  95.4% -- replaced /opt/testing3/cat3.log.gz /opt/testing3/cat4.log:  95.4% -- replaced /opt/testing3/cat4.log.gz /opt/testing3/cat5.log:  95.4% -- replaced /opt/testing3/cat5.log.gz /opt/testing3/cat6.log:  95.4% -- replaced /opt/testing3/cat6.log.gz /opt/testing3/cat7.log:  95.4% -- replaced /opt/testing3/cat7.log.gz

why output different? seems awk not executed.

you have escape "$" symbol, in order not locally, pass remotely.

$ ssh $hostname "ls -l /tmp | tail -1 | awk '{print $6}'" -rw-r--r-- 1 root     root       0 apr 29 01:31 file.log $ ssh $hostname "ls -l /tmp | tail -1 | awk '{print \$6}'" apr

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