linux - Printing more than one line after a match - 


$ cat /etc/sudoers     inavg7ey evl0000332,evl0000333,evl0000234,evl0000999,evs99234456,\\  evl3300987,evl3344567,evlser999,eul000123,evs3300123,evs3300124,\\ (root,jboss,superss) nopasswd:all  inavgmcn evl0000332,evl0000333,evl0000234,evl0000999=(all,wasadmin,\\ jboss,superss) nopasswd:all

i want print inavg7ey user details second line (if more lines there want them also).. me this? i've tried this:

awk '/inavg7ey/' /etc/sudoers

but it's displaying one:

inavg7ey evl0000332,evl0000333,evl0000234,evl0000999,evs99234456,\

you may use:

awk '/inavg7ey/{c=n}c&&c--' /etc/sudoers

n - here number of line after match including match

and 1 solution:

awk '/navg7ey/,/^$/' /etc/sudoers

awk -may grep between 2 patterns, in file,
navg7ey - it's first pattern grep from;
^$ - it's second pattern grep (^$ - means empty line)


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