Compare two columns, but only first 4 letters - vba excel -
i have 2 columns - column , column b, filled different items. column b shorter (it has less items column a). need vba formula in excel 2007 following:
1) compare first 4 letters of items in column b first 4 letters of items column
2) find match in column , copy whole content of cell in column column c, next item in column b matched.
here's i've made far:
sub compare() dim range1 range, range2 range, rng1 range, rng2 range dim x long xtitleid = "compare" set range1 = application.selection set range1 = application.inputbox("range1 :", xtitleid, range1.address, type:=8) set range2 = application.inputbox("range2:", xtitleid, type:=8) application.screenupdating = false each rng1 in range1 xvalue = rng1.value each rng2 in range2 x = rng2.row if xvalue = rng2.value rng1.copy activesheet.range("c" & x).pastespecial end if next next application.screenupdating = true end sub this code job, compares whole words , need first 4 letters. know of function left, don't know how implement here. can me?
the function need following:
test = left("yourvalue",4) of course there opposite function:
test = right("yourvalue",5) in firts case result in test "your" , in second case "value"
to copy value in colum c can use 2 strategy:
activesheet.range("c" & x).cells(row_index, column_index) or
activesheet.range("c" & x).pastespecial
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