regex - scala parsing next line -

i've got text

--make_123 say:hello  say:bye --make_123-- 

i need parse map:

{   makeid : 123   firstnode : hello   secondnode : bye } 

i've got following scala code:

class myparser extends regexparsers {    def parsetext(input: string): mapcontent = parseall(parserequest, input) match {     case success(result, _) => result     case nosuccess(msg, _) => throw new someexception(msg)   }    def parserequest: parser[mapcontent] = parsemakeid ~ parsetext ^^ {     case makeid ~ firstnode => {       mapcontent(         map("makeid" -> makeid) ++           map("firstnode" -> firstnode))     }   }     def parsemakeid: parser[string] = "--make_" ~> ".*".r    def parsetext: parser[string] = "say:" ~> ".*".r  }  case class mapcontent(map: map[string, string]) 

well, here receive

string matching regex `.*\z$' expected `s' found 

which second line , first literal of "say:"

how parse text? how omit empty line on 3rd line? thx

here assume, text parse contains 2 nodes , don't want check line --make_123-- valid (i.e., has same id first line).

you don't have omit empty line manually. gets skipped automatically, because it's whitespace.

you using parseall, means parser should match whole text sent it. have add grammar code parse second line , closing line --make_123--.

that's simple parser functions have defined, , slight modification function producing mapcontent parsed result.

the parserequest function should changed have following definition:

  def parserequest: parser[mapcontent] =      parsemakeid ~ parsetext ~ parsetext <~ parsemakeid ^^ {       case makeid ~ firstnode ~ secondnode =>         mapcontent(           map("makeid" -> makeid,               "firstnode" -> firstnode,               "secondnode" -> secondnode))   }