regex - Parsing links from html with gawk -


i'm trying take googles html, , parse out links. use curl obtain html pass gawk. gawk used match() function, , works returns small amount of links. maybe 10 @ most. if test regex on regex101.com returns 51 links using g global modifier. how can use in gawk obtain links (relative , absolute)?

#!/bin/bash  html=$(curl -l "http://google.com")  echo "${html}" | gawk '   begin {     rs=" "     ignorecase=1   }   {     match($0, /href=\"([^\"]*)/, array);     if (length(array[1]) > 0) {       print array[1];     }   }'

instead of awk can use grep -op:

curl -sl "http://google.com" | grep -ipo 'href="\k[^"]+'

however fetching 31 links me. may vary browser because google.com serves different page different locations/signed in users.


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