javascript - How to fade image src attribute? -


i found can done this:

$(".topimage img")         .mouseover(function() {              var src = $(this).attr("src").match(/[^\.]+/) + "-bw.png";             $(this).fadeout("fast").attr("src", src).fadein("fast");         })         .mouseout(function() {             var src = $(this).attr("src").replace("-bw.png", ".png");                             $(this).fadeout("fast").attr("src", src).fadein("fast");         });     });

but makes bad because fades previous src out completely. there way transition src change there no "now it's white background before new src loads in" ?

edit

<div class="topimage">     <img src="<?=$img[0]?>"> </div>

this how must remain - 1 image in topimage container haveing 2 images change opacity, not option.

you can without js @ all. there lot of way it, here 1 : http://codepen.io/mbrillaud/pen/mwwgwz

html

<div class="container">   <img src="//lorempicsum.com/futurama/350/200/2" alt="" />   <img src="//lorempicsum.com/futurama/350/200/1" alt="" /> </div>

css

.container {   position: relative; }  .container img {   position: absolute;   top: 0;   left: 0;   transition: opacity 0.5s; } .container img:last-child:hover{   opacity: 0; }

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