javascript - Jquery Ajax Request Not Working -


i tried send form data via jquery ajax request server , display response of php file located on server, in <div id=”response-box”></div>. when submit form nothing happened. mistake? tried 3 days solve this. me. thank you!

i tested on localhost (wamp server)

this html code on index.html

<form id="myform">   <input type="text" id="fname">   <input type="text" id="lname">   <input type="submit" id="data-send-button" value="send data">  </form>  <div id="responce-box"> </div>

this jquery ajax request on app.js

$(document).ready(function(){      $('form#myform').on('submit' , function(){         $.ajax({          url:"submit.php" ,          type: "post" ,         data: {fname: $('#fname').val(), lname: $('#lname').val()} ,          success: function(data){         $('#responce-box').html(data);}           });       });  });

this php code on submit.php (localhost/wamp server)

<?php  $fname = $_post['fname']; $lname = $_post['lname'];  echo $name $lname;  // code data sending mysql data base

no when click submit button, text values in text boxes disappeared

looking @ code, using $.ajax request when clicking submit button. means that, form reacted normal form refresh page. if want request ajax, should disable default behavior of form using preventdefault() code. , did't see error in js code.

change js code :

$(document).ready(function(){  $('form#myform').on('submit' , function(e){     e.preventdefault();//<--add here ---^    $.ajax({      url:"submit.php" ,      type: "post" ,     data: {fname: $('#fname').val(), lname: $('#lname').val()} ,      success: function(data){     $('#responce-box').html(data);}       });   });  });

some error in php code. try following code :

$fname = $_post['fname']; $lname = $_post['lname'];  echo $fname.$lname;

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