java - Restlet stop server after exactly one request is handled -


i want use restlet create local server. server should receive exaclty 1 request (besides favicon), , after request handled should shut down. don't want use system.exit, want shut down properly.

as can see in code commented line when assume request handled properly. can't tell server stop there.

how can tell server stop waiting requests @ point? got working 2 issues i'd solve.

  • i exceptions when stop server within request

  • the response sent client not shown if stop server within request

    public class main {  public static void main(string[] args){     server serv = null;      restlet restlet = new restlet() {         @override         public void handle(request request, response response) {            if(!request.tostring().contains("favicon")){               system.out.println("do stuff");               response.setentity("request handled", mediatype.text_plain);               //stop server after first request handled.                //so program should shut down here               //if use serv.stop() here (besides it's not final)               //i'd exceptions , user wouldn't see response           }         }     };        // avoid conflicts other java containers listening on 8080!     try {         serv = new server(protocol.http, 8182, restlet);          serv.start();     } catch (exception e) {         // todo auto-generated catch block         e.printstacktrace();     } }  }

i figured out way it. add onsent event response, , shut down server here.

public class main {      private server serv;      public main(){         run();     }      public void run(){              restlet restlet = new restlet() {                 @override                 public void handle(request request, response response) {                     response.setentity("request handled", mediatype.text_plain);                   if(!request.tostring().contains("favicon")){                       system.out.println("do stuff");                        response.setonsent(new uniform() {                          @override                         public void handle(request req, response res) {                              try {                                 serv.stop();//stop server                             } catch (exception e) {                                 // todo auto-generated catch block                                 e.printstacktrace();                             }                         }                     });                    }                 }             };              // avoid conflicts other java containers listening on 8080!             try {                 serv = new server(protocol.http, 8182, restlet);                  serv.start();             } catch (exception e) {                 // todo auto-generated catch block                 e.printstacktrace();             }     }      public static void main(string[] args){          new main();      }  }

Comments

Post a Comment

Popular posts from this blog

php - failed to open stream: HTTP request failed! HTTP/1.0 400 Bad Request -

this code i'm using find latitude , longitude of place: function coords($address){ echo $url="http://maps.googleapis.com/maps/api/geocode/json?address=".$address; $json = file_get_contents(urlencode($url)); $data = json_decode($json, true); print_r($data['results'][0]['geometry']['location']['lat']); print_r($data['results'][0]['geometry']['location']['lng']); } however returns warning: failed open stream: http request failed! http/1.0 400 bad request if use above code in simple procedure works fine not in function. note: have tried curl_init()... method produced same result? instead of encoding whole url encode address part. following code work fine $add='jamshoro phase 2'; $url="http://maps.googleapis.com/maps/api/geocode/json?address=".urlencode($add); $json = file_get_contents($url); $data = json_decode($json, true); print_r($data['r
Read more

java - How to filter a backspace keyboard input -

i have code gives message when key number pressed: txtvalueofclause.addeventfilter(keyevent.key_typed, new eventhandler<keyevent>() { @override public void handle(keyevent t) { char ar[] = t.getcharacter().tochararray(); char ch = ar[t.getcharacter().tochararray().length - 1]; if (!(ch >= '0' && ch <= '9')) { system.out.println("the char entered not number"); t.consume(); } } }); now if press on wrong button , press backspace remove it, error message. how can add backspace input if statement? i have found answer: txtvalueofclause.addeventfilter(keyevent.key_typed, new eventhandler<keyevent>() { @override public void handle(keyevent t) { char ar[] = t.getcharacter().tochararray(); char ch = ar[t.getcharacter().tochar
Read more

java - Show Soft Keyboard when EditText Appears -

i have code in android app, alert dialog , keyboard, , when dialog shown want keyboard appear. not , not sure why? here code: final alertdialog.builder alert = new alertdialog.builder(this); alert.settitle("title"); alert.setmessage("message"); final edittext input = new edittext(this); input.setinputtype(inputtype.type_class_number); alert.setview(input); input.setonfocuschangelistener(new view.onfocuschangelistener() { @override public void onfocuschange(view v, boolean hasfocus) { if (hasfocus) { log.i(tag, "in focus"); inputmethodmanager inputmethodmanager = (inputmethodmanager) getsystemservice(context.input_method_service); inputmethodmanager.showsoftinput(input, inputmethodmanager.show_implicit); } } }); but keyboard not appear though edit text in focus, , tell appear why, doesn't come up? thanks in advance.
Read more