regex - JavaScript RegExp error - Nothing to repeat -


i have wrote regex match html text , works in regex101.com.

<h2>dollarkurs\saktuell<\/h2><\/div><div[^>?]+><div><table> <colgroup><col[^>?]+><col><col[^>?]+><\/colgroup><tbody><tr> <td[^>?]+>kurs<\/td><td[^>?]+>([^\s^<?]+)\s*<span[^>?]+> (\+|-)?\d+\,?\d{0,2}%<\/span><span[^>?]+><\/span><\/td> <\/tr><tr><td[^>?]+>kurszeit<\/td><td[^>?]+> (([0-1]?[0-9])|([2][0-3])):([0-5]?[0-9])(:([0-5]?[0-9]))?\suhr <\/td><\/tr><tr><td[^>?]+>kursdatum<\/td><td[^>?]+>([0-9\.]+)<\/td>

the test string is:

<h2>dollarkurs aktuell</h2></div><div class='content'><div><table> <colgroup><col width='50px'><col><col width='100px'></colgroup><tbody><tr> <td class='bold'>kurs</td><td class='textright' colspan='2'>1,0947 <span class='distanceleft right green'> +0,58%</span><span class='distanceleft right imageiconpricegreen'></span></td> </tr><tr><td class='bold' colspan='2'>kurszeit</td><td class='textright'> 16:00:00 uhr </td></tr><tr><td class='bold' colspan='2'>kursdatum</td><td class='textright'>28.04.2015</td>

but in program, i'm getting error:

 uncaught syntaxerror: invalid regular expression:  nothing repeat

here code:

var htmltxt = "<h2>dollarkurs aktuell</h2></div><div class='content'><div><table><colgroup><col width='50px'><col><col width='100px'></colgroup><tbody><tr><td class='bold'>kurs</td><td class='textright' colspan='2'>1,0947 <span class='distanceleft right green'>+0,58%</span><span class='distanceleft right imageiconpricegreen'></span></td></tr><tr><td class='bold' colspan='2'>kurszeit</td><td class='textright'>16:00:00 uhr</td></tr><tr><td class='bold' colspan='2'>kursdatum</td><td class='textright'>28.04.2015</td>";  var re = new regexp("<h2>dollarkurs\saktuell<\/h2><\/div><div[^>?]+><div><table><colgroup><col[^>?]+><col><col[^>?]+><\/colgroup><tbody><tr><td[^>?]+>kurs<\/td><td[^>?]+>([^\s^<?]+)\s*<span[^>?]+>(\+|-)?\d+\,?\d{0,2}%<\/span><span[^>?]+><\/span><\/td><\/tr><tr><td[^>?]+>kurszeit<\/td><td[^>?]+>(([0-1]?[0-9])|([2][0-3])):([0-5]?[0-9])(:([0-5]?[0-9]))?\suhr<\/td><\/tr><tr><td[^>?]+>kursdatum<\/td><td[^>?]+>([0-9\.]+)<\/td>", "gmi");  var result = re.exec(htmltxt);  while (result != null)  {   document.write("["+re.lastindex+"] "+result);   document.write("<br />");  }

with no regard whether pattern correct or not:

instead of using:

var re = new regexp("\+", "gmi");

use:

var re = /\+/gmi;

see mdn - creating regular expression.

if using string constructor, need string-escape backslashes:

var re = new regexp("\\+", "gmi");

as mentioned in comments, parsing html regexp not idea, especially in browser using javascript, since in context of giant html parser.


Comments

Post a Comment

Popular posts from this blog

php - failed to open stream: HTTP request failed! HTTP/1.0 400 Bad Request -

this code i'm using find latitude , longitude of place: function coords($address){ echo $url="http://maps.googleapis.com/maps/api/geocode/json?address=".$address; $json = file_get_contents(urlencode($url)); $data = json_decode($json, true); print_r($data['results'][0]['geometry']['location']['lat']); print_r($data['results'][0]['geometry']['location']['lng']); } however returns warning: failed open stream: http request failed! http/1.0 400 bad request if use above code in simple procedure works fine not in function. note: have tried curl_init()... method produced same result? instead of encoding whole url encode address part. following code work fine $add='jamshoro phase 2'; $url="http://maps.googleapis.com/maps/api/geocode/json?address=".urlencode($add); $json = file_get_contents($url); $data = json_decode($json, true); print_r($data['r
Read more

java - How to filter a backspace keyboard input -

i have code gives message when key number pressed: txtvalueofclause.addeventfilter(keyevent.key_typed, new eventhandler<keyevent>() { @override public void handle(keyevent t) { char ar[] = t.getcharacter().tochararray(); char ch = ar[t.getcharacter().tochararray().length - 1]; if (!(ch >= '0' && ch <= '9')) { system.out.println("the char entered not number"); t.consume(); } } }); now if press on wrong button , press backspace remove it, error message. how can add backspace input if statement? i have found answer: txtvalueofclause.addeventfilter(keyevent.key_typed, new eventhandler<keyevent>() { @override public void handle(keyevent t) { char ar[] = t.getcharacter().tochararray(); char ch = ar[t.getcharacter().tochar
Read more

java - Show Soft Keyboard when EditText Appears -

i have code in android app, alert dialog , keyboard, , when dialog shown want keyboard appear. not , not sure why? here code: final alertdialog.builder alert = new alertdialog.builder(this); alert.settitle("title"); alert.setmessage("message"); final edittext input = new edittext(this); input.setinputtype(inputtype.type_class_number); alert.setview(input); input.setonfocuschangelistener(new view.onfocuschangelistener() { @override public void onfocuschange(view v, boolean hasfocus) { if (hasfocus) { log.i(tag, "in focus"); inputmethodmanager inputmethodmanager = (inputmethodmanager) getsystemservice(context.input_method_service); inputmethodmanager.showsoftinput(input, inputmethodmanager.show_implicit); } } }); but keyboard not appear though edit text in focus, , tell appear why, doesn't come up? thanks in advance.
Read more