javascript - Implementating wizard (jquery.steps) in Yii2 framework -


i implement wizard (with forms) application. therefore, use jquery.steps (which can find here.

i have created assetbundle containing correct js files 

namespace app\assets;  use yii\web\assetbundle;   class wizardasset extends assetbundle { public $basepath = '@webroot'; public $baseurl = '@web'; public $css = [     'css/site.css',     'css/smart_wizard.css',     'css/jquery.steps.css', ]; public $js = [     'js/jquery.steps.min.js', ];  public $depends = [     'yii\web\yiiasset',     'yii\bootstrap\bootstrapasset', ]; }

and have following code in view:

<?php use app\assets\wizardasset; wizardasset::register($this); ?>  <div id="example-basic">     <h3>keyboard</h3>     <section>         <p>try keyboard navigation clicking arrow left or right!</p>     </section>     <h3>effects</h3>     <section>         <p>wonderful transition effects.</p>     </section>     <h3>pager</h3>     <section>         <p>the next , previous buttons navigate through content.</p>     </section> </div>  <script> $("#example-basic").steps({     headertag: "h3",     bodytag: "section",     transitioneffect: "slideleft",     autofocus: true }); </script>

this not seem work: guess javascript files should loaded before .. @ end of html file, yii forces script @ end of file. there way overcome this? or correct mistake?


Comments

Post a Comment

Popular posts from this blog

php - failed to open stream: HTTP request failed! HTTP/1.0 400 Bad Request -

this code i'm using find latitude , longitude of place: function coords($address){ echo $url="http://maps.googleapis.com/maps/api/geocode/json?address=".$address; $json = file_get_contents(urlencode($url)); $data = json_decode($json, true); print_r($data['results'][0]['geometry']['location']['lat']); print_r($data['results'][0]['geometry']['location']['lng']); } however returns warning: failed open stream: http request failed! http/1.0 400 bad request if use above code in simple procedure works fine not in function. note: have tried curl_init()... method produced same result? instead of encoding whole url encode address part. following code work fine $add='jamshoro phase 2'; $url="http://maps.googleapis.com/maps/api/geocode/json?address=".urlencode($add); $json = file_get_contents($url); $data = json_decode($json, true); print_r($data['r
Read more

java - How to filter a backspace keyboard input -

i have code gives message when key number pressed: txtvalueofclause.addeventfilter(keyevent.key_typed, new eventhandler<keyevent>() { @override public void handle(keyevent t) { char ar[] = t.getcharacter().tochararray(); char ch = ar[t.getcharacter().tochararray().length - 1]; if (!(ch >= '0' && ch <= '9')) { system.out.println("the char entered not number"); t.consume(); } } }); now if press on wrong button , press backspace remove it, error message. how can add backspace input if statement? i have found answer: txtvalueofclause.addeventfilter(keyevent.key_typed, new eventhandler<keyevent>() { @override public void handle(keyevent t) { char ar[] = t.getcharacter().tochararray(); char ch = ar[t.getcharacter().tochar
Read more

java - Show Soft Keyboard when EditText Appears -

i have code in android app, alert dialog , keyboard, , when dialog shown want keyboard appear. not , not sure why? here code: final alertdialog.builder alert = new alertdialog.builder(this); alert.settitle("title"); alert.setmessage("message"); final edittext input = new edittext(this); input.setinputtype(inputtype.type_class_number); alert.setview(input); input.setonfocuschangelistener(new view.onfocuschangelistener() { @override public void onfocuschange(view v, boolean hasfocus) { if (hasfocus) { log.i(tag, "in focus"); inputmethodmanager inputmethodmanager = (inputmethodmanager) getsystemservice(context.input_method_service); inputmethodmanager.showsoftinput(input, inputmethodmanager.show_implicit); } } }); but keyboard not appear though edit text in focus, , tell appear why, doesn't come up? thanks in advance.
Read more