How to C# linq GroupBy multiple arrays with array values -


i have array of objects "channel" each have properties

string axis  //times , values correspond each other. lengths same. times[0] value values[0], etc...    float[] times float[] values

lets there 3 channels in channels array, , float[] "times" values are...

channel[0].times = 1, 2, 3, 4, 5, 6 channel[1].times = 0, 2, 2.5, 3, 5, 6 channel[2].times = 1, 2.5, 3, 4, 5.5, 6

minichannel object has properties

string axis float value;

the result looking this...

dictionary<float, minichannel[]> matchingtimes; //float corresponds times value

matchingtimes[0] contains...

new minichannel0 minichannel.axis = channel[1].axis minichannel.value= channel[1].values[0]

matchingtimes[1] contains...

new minichannel0 minichannel.axis = channel[0].axis minichannel.value= channel[0].values[0]  new minichannel1 minichannel.axis = channel[2].axis minichannel.value = channel[2].values[0]

.....

matchingtimes[5.5] contains...

new minichannel0 minichannel.axis = channel[2].axis minichannel.value= channel[2].values[4]

etc... etc... each time value.

so trying group channels same time , value time string axis.

ive looked around answers in regards groupby linq method, saw people dealing either single array, or array multiple elements, still 1 item each element.

any appreciated.

try this:

idictionary<float, minichannel[]> matchingtimes = channel     .selectmany(c => c.times.select((t, i) => new keyvaluepair<float, minichannel>(t, new minichannel {axis = c.axis, value = c.values[i]})))     .groupby(t => t.key)     .todictionary(t => t.key, t => t.select(c => c.value).toarray());

Comments

Post a Comment

Popular posts from this blog

php - failed to open stream: HTTP request failed! HTTP/1.0 400 Bad Request -

this code i'm using find latitude , longitude of place: function coords($address){ echo $url="http://maps.googleapis.com/maps/api/geocode/json?address=".$address; $json = file_get_contents(urlencode($url)); $data = json_decode($json, true); print_r($data['results'][0]['geometry']['location']['lat']); print_r($data['results'][0]['geometry']['location']['lng']); } however returns warning: failed open stream: http request failed! http/1.0 400 bad request if use above code in simple procedure works fine not in function. note: have tried curl_init()... method produced same result? instead of encoding whole url encode address part. following code work fine $add='jamshoro phase 2'; $url="http://maps.googleapis.com/maps/api/geocode/json?address=".urlencode($add); $json = file_get_contents($url); $data = json_decode($json, true); print_r($data['r
Read more

java - How to filter a backspace keyboard input -

i have code gives message when key number pressed: txtvalueofclause.addeventfilter(keyevent.key_typed, new eventhandler<keyevent>() { @override public void handle(keyevent t) { char ar[] = t.getcharacter().tochararray(); char ch = ar[t.getcharacter().tochararray().length - 1]; if (!(ch >= '0' && ch <= '9')) { system.out.println("the char entered not number"); t.consume(); } } }); now if press on wrong button , press backspace remove it, error message. how can add backspace input if statement? i have found answer: txtvalueofclause.addeventfilter(keyevent.key_typed, new eventhandler<keyevent>() { @override public void handle(keyevent t) { char ar[] = t.getcharacter().tochararray(); char ch = ar[t.getcharacter().tochar
Read more

java - Show Soft Keyboard when EditText Appears -

i have code in android app, alert dialog , keyboard, , when dialog shown want keyboard appear. not , not sure why? here code: final alertdialog.builder alert = new alertdialog.builder(this); alert.settitle("title"); alert.setmessage("message"); final edittext input = new edittext(this); input.setinputtype(inputtype.type_class_number); alert.setview(input); input.setonfocuschangelistener(new view.onfocuschangelistener() { @override public void onfocuschange(view v, boolean hasfocus) { if (hasfocus) { log.i(tag, "in focus"); inputmethodmanager inputmethodmanager = (inputmethodmanager) getsystemservice(context.input_method_service); inputmethodmanager.showsoftinput(input, inputmethodmanager.show_implicit); } } }); but keyboard not appear though edit text in focus, , tell appear why, doesn't come up? thanks in advance.
Read more