java - How can I sort a Map according to the parameters of its values? -


this question has answer here:

stream<map.entry<string, list<object>>> sorted = index.entryset().stream()                 .sorted(map.entry.comparingbyvalue());

the method sorted(comparator<? super map.entry<string,list<nfarticle>>>) in type stream<map.entry<string,list<nfarticle>>> not applicable arguments (comparator <map.entry<object,comparable<? super comparable<? super v>>>>)

i want sort hashmap according size() of lists being values of hashmap. how can achieve using stream library java 8?

this may helpful you.

i changed type of result map linkedhashmap respect insertion order.

public static void main(string[] args) {     final map<string, list<integer>> map = new hashmap<>();     map.put("k1", arrays.aslist(new integer[]{1, 2, 3, 4, 5}));     map.put("k2", arrays.aslist(new integer[]{1, 2, 3, 4, 5, 6}));     map.put("k3", arrays.aslist(new integer[]{1, 2, 3}));     system.out.println(getmapsortedbylistsize(map)); }  public static <k, v> map<k, list<v>> getmapsortedbylistsize(final map<k, list<v>> map) {     return map.entryset().stream()             .sorted((e1, e2) -> e1.getvalue().size() - e2.getvalue().size())             .collect(collectors.tomap(map.entry::getkey, map.entry::getvalue, (a, b) -> a, linkedhashmap::new)); }

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