java - How to join items of list, but use a different delimiter for the last item? -

given list like:

list<string> names = lists.newarraylist("george", "john", "paul", "ringo")

i'd transform string this:

george, john, paul , ringo

i can rather clumsy stringbuilder thing so:

string namelist = names.stream().collect(joining(", "));         if (namelist.contains(",")) {             stringbuilder builder = new stringbuilder(namelist);             builder.replace(namelist.lastindexof(','), namelist.lastindexof(',') + 1, " and");             return builder.tostring();         } 

is there bit more elegant approach? don't mind using library if needed.

notes:

• i use old for loop index, not looking such solution
• there no commas within values (names)

as did of introduce second method "replacelast" not in jdk java.lang.string far:

import java.util.list; import java.util.stream.collectors;  public final class stringutils {  private static final string , = " , ";  private static final string comma = ", ";   // initial call wrapped replacelast call  public static string asliteralnumeration(list<string> strings) {     return replacelast(strings.stream().collect(collectors.joining(comma)), comma, and);  }   public static string replacelast(string text, string regex, string replacement) {     return text.replacefirst("(?s)" + regex + "(?!.*?" + regex + ")", replacement);  } } 

you might change delimiters , params well. here test requirements far:

@org.junit.test public void test() {  list<string> names = arrays.aslist("george", "john", "paul", "ringo");  assertequals("george, john, paul , ringo", stringutils.asliteralnumeration(names));   list<string> oneitemlist = arrays.aslist("paul");  assertequals("paul", stringutils.asliteralnumeration(oneitemlist));   list<string> emptylist = arrays.aslist("");  assertequals("", stringutils.asliteralnumeration(emptylist));  }