algorithm - Finding Connected Components -


i want find connected components of directed acyclic graph using set of nodes. efficient way solve problem?

connected component: if 1 of nodes predecessor or successors of node, in same connected component.

for example, let's have following graph , vector = [2,4,5,6,3]. vector, there 2 connected component below.

c1 = [2,4,5,6] c2 = [3]

enter image description here

my solution:

  • sort nodes using depth value
  • pick node
  • check other nodes if successors or not. if so, keep looking. if not, stop , go step 2.

what think?

i hope understand definition of connected component...if that's case

i agree @anonymous, can make graph undirected , find connected components using simple dfs...

i not quite understand original thought, @ least think implementation bit complicated, edges {1-->2, 2-->4, 3-->4}, node #1 , #3 sorted @ beginning of list, , how can know {1,2,3,4} single connected component?

anyhow, complexity same simple dfs method, @ best, o(v)

(if think answer correct, please give credits @anonymous!)


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