php - magic __get() on end($array) or $var -

i want access last element of array via php's magic __get method.

i using php's end($array) return.

if this:

class fun {   protected $var = 'test';   protected $arr = array(1, 2);    public function __get($name) {     return $this->$name;   }    public function get_array() {     return end($this->arr);   } }  $obj = new fun(); var_dump($obj->var); //gives me: string(4) "test" var_dump($obj->get_array()); //gives me: int(2); 

everything working fine. far good.

i don't want use different "getters" vars , arrays. want method find out if variable or array called , return value.

i thought easy done via $name parameter, too:

class funfun {   protected $var = 'more test';   protected $arr = array(1, 2, 3);    public function __get($name) {     if(is_array($this->$name)) {       $ret = end($this->$name);     } else {       $ret = $this->$name;     }      return $ret;     } }  $obj2 = new funfun(); var_dump($obj2->var); //gives me string(9); 

but

var_dump($obj2->arr); // gives me: //array(3) {[0]=> int(1) [1]=> int(2) [2]=> int(3)} 

if dump within __get() method:

public function __get($name) {   if(is_array($this->$name)) {     var_dump(end($this->$name));   } 

it giving me "right" result: int(3).

am missing something? semantic-error? php's return not designed purpose?

so problem (at least here @ home) seems "get"-call within __construct method. forgot check in original-code.

public function __construct() {   $x = $this->arr;    var_dump($x);  } 

gives us:

//array(3) {[0]=> int(1) [1]=> int(2) [2]=> int(3)} 

but:

$obj2 = new _funfun();  $x = $obj2->arr; var_dump($x); 

shows result: int(3).

i have further ath under 5.3.10-1ubuntu3.17 @ work tomorrow. on home machine 5.6.8 working intended.