javascript - Display unobtrusive message for jquery autocomplete field -


i can't seem find answer problem. have simple jquery autocomplete field , entry required model. when check validation method not highlighted.

 <tr>             <td>                 <b style="color:red">*</b>find user id or enter new:<br />                 @html.validationmessagefor(x=>x.userid)             </td>             <td>                 <input id="users" class="usermodel" style="text-transform:uppercase" />                 @html.hiddenfor(x=>x.userid, new { @id = "txtuserid" })             </td>         </tr>   $("#users").autocomplete({         delay: 0,         minlength: 0,         autofocus: true,         source: function (request, response) {             $.ajax({                 type: 'post',                 data: { 'data': request.term },                 datatype: 'json',                 url: '@url.action("getallusers")',                 success: function (data) {                     response($.map(data, function (obj) {                         return {                             value: obj                         }                     }));                 }             });         },         select: function (event, ui) {             neworold = "old";             $.ajax({                 type: 'get',                 datatype: 'json',                 url: '@url.action("getuser")',                 data: { userid: ui.item.label },                 success: function (data) {                     $("#txtusername").val(data.username);                     $("#ddluserrole").val(data.userrole);                     $("#chkuseradmin").prop("checked", data.admin);                     $("#chkusertrans").prop("checked", data.trans);                     $("#chkuserreports").prop("checked", data.reports);                     $("#txtuserid").val(data.userid);                 },                 error: function (xhr) {                     var err = xhr.responsetext;                     alert('error');                 }             });         }     }).focus(function () {         $("#users").autocomplete('search', $("#users").val());     }).blur(function () {         var keyevent = $.event("keydown");         keyevent.keycode = $.ui.keycode.enter;         $(this).trigger(keyevent);         if (neworold != "old") {             $("#txtuserid").val($("#users").val());         }     });      if (!$("#userform").valid()) {         return false;     }


Comments

Post a Comment

Popular posts from this blog

php - failed to open stream: HTTP request failed! HTTP/1.0 400 Bad Request -

this code i'm using find latitude , longitude of place: function coords($address){ echo $url="http://maps.googleapis.com/maps/api/geocode/json?address=".$address; $json = file_get_contents(urlencode($url)); $data = json_decode($json, true); print_r($data['results'][0]['geometry']['location']['lat']); print_r($data['results'][0]['geometry']['location']['lng']); } however returns warning: failed open stream: http request failed! http/1.0 400 bad request if use above code in simple procedure works fine not in function. note: have tried curl_init()... method produced same result? instead of encoding whole url encode address part. following code work fine $add='jamshoro phase 2'; $url="http://maps.googleapis.com/maps/api/geocode/json?address=".urlencode($add); $json = file_get_contents($url); $data = json_decode($json, true); print_r($data['r
Read more

java - How to filter a backspace keyboard input -

i have code gives message when key number pressed: txtvalueofclause.addeventfilter(keyevent.key_typed, new eventhandler<keyevent>() { @override public void handle(keyevent t) { char ar[] = t.getcharacter().tochararray(); char ch = ar[t.getcharacter().tochararray().length - 1]; if (!(ch >= '0' && ch <= '9')) { system.out.println("the char entered not number"); t.consume(); } } }); now if press on wrong button , press backspace remove it, error message. how can add backspace input if statement? i have found answer: txtvalueofclause.addeventfilter(keyevent.key_typed, new eventhandler<keyevent>() { @override public void handle(keyevent t) { char ar[] = t.getcharacter().tochararray(); char ch = ar[t.getcharacter().tochar
Read more

java - Show Soft Keyboard when EditText Appears -

i have code in android app, alert dialog , keyboard, , when dialog shown want keyboard appear. not , not sure why? here code: final alertdialog.builder alert = new alertdialog.builder(this); alert.settitle("title"); alert.setmessage("message"); final edittext input = new edittext(this); input.setinputtype(inputtype.type_class_number); alert.setview(input); input.setonfocuschangelistener(new view.onfocuschangelistener() { @override public void onfocuschange(view v, boolean hasfocus) { if (hasfocus) { log.i(tag, "in focus"); inputmethodmanager inputmethodmanager = (inputmethodmanager) getsystemservice(context.input_method_service); inputmethodmanager.showsoftinput(input, inputmethodmanager.show_implicit); } } }); but keyboard not appear though edit text in focus, , tell appear why, doesn't come up? thanks in advance.
Read more