UnboundLocalError: local variable 'X' referenced before assignment Python for simbols fixer -


i have simbols fixer in python latex made code , dont know why shows 

traceback (most recent call last):   file "c:\users\stark's probook\desktop\prueba.py", line 92, in <module>     bracketfind()   file "c:\users\stark's probook\desktop\prueba.py", line 30, in bracketfind     h in archivo: unboundlocalerror: local variable 'archivo' referenced before assignment

this code python 2.7

# -*- coding: cp1252 -*-  archivo = open("test.txt", "r") texto = archivo.readlines() archivo = "".join(texto) opening = 0 closes = 0 print archivo        def count():     return contador('{')-contador('}')  def contador(simbolo):     conta = 0     h in archivo:         if simbolo == h:             conta= conta+1     return conta  def insert(string, index):     return string[:index] + '.' + string[index:]  def remove(string, index):     return string[:index-1] + '.' + string[index+1:]  def bracketfind():      opening = 0     closes = 0     h in archivo:         if '{' == h:             opening = opening+1         elif '}' ==h:             closes = closes+1      print "abiertas ({) "+ str(opening) + " cerradas (}) "+str(closes)     position = -1     startreplacing = false     openposition = -1     while true:         position = -1         startreplacing = false         openposition = -1         if count() == 0:             print "revision exitosa!!, no existe ninguna { sin cerrar " +"si tienes problemas de compilacion no es por esta razón. " + "revisa tu codigo en busca de otro error"             return true         if contador('{') == 0 , contador('}')>0:             break         if contador('{') > 0 , contador('}') == 0:             break         character in archivo:             position = position+1             if character == '{':                 openposition = position                 startreplacing = true             if startreplacing:                 if character == '}':                     try:                         archivo = remove(archivo,openposition)                         archivo = insert(archivo,openposition)                         archivo = remove(archivo,position)                         archivo = insert(archivo,position)                     except:                         break     ipos = -1     icount = -1     itarget = 0     itype = 0      if '{' in archivo:         itarget = archivo.rfind('{')         print itarget         itype = 1     elif '}' in archivo:             itarget = archivo.rfind('}')             itype = 2     if itarget == -1:         return true     if itype == 1:         print "la llave que abre (" , itarget , ") quizas es inecesaria o parece no estar cerrada"     elif itype == 2:             print "la llave que cierra (" , itarget , ") quizas es inecesaria o parece no estar cerrada"     character in archivo:         ipos = ipos+1         if character == '{' or character == '}':             icount = icount+1             if(icount == itarget):                print "la llave ",icount , "parece tener error"     return true  print count() bracketfind()

do have idea causing this? dont understand why showing if @ begin of execution prints 'archivo'

this has how python handles scopes. initially, archivo global variable, defined outside function or class; can accessed scope. bracketfind() includes several definitions archivo, ie 'archivo = remove(archivo,openposition)'. causes archivo revert local scope function; global variable trying refer no longer accessible.

the easiest way fix add line 'global archivo' near beginning of bracketfind(), more robust solution rework code archivo no longer global variable.


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