c# - (createchildcontrole) = object reference not set to an instance of an object -


i use visual studio 2012 create usercontrols wrapped on sharepoint 2010 following code of 1 of them 

    public partial class sidebarusercontrol : system.web.ui.usercontrol {     protected void page_load(object sender, eventargs e)     {         lilogout.visible = false;         attendance.visible = false;         empevaluation.visible = false;         objections.visible = false;         myeval.visible = false;         rates.visible = true;         if (pagebase.currentuser == null)         {             string loginname = spcontext.current.web.currentuser.loginname;             loginname = loginname.split(new string[] { "\\" }, stringsplitoptions.removeemptyentries)[1];              if (systemuserbll.isuserexist(loginname, "123456"))             {                 systemuserbll.login(loginname, "123456");             }             else                 response.redirect("login.aspx", true);         }          if (new userdal().getuserfieldvalue(pagebase.currentuser.id, 51).fieldvalue == "الدرجة الثانية")         {             rates.visible = false;             syssettings.visible = false;             reports.visible = false;             string employeetype = new userdal().getuserfieldvalue(pagebase.currentuser.id, 39).value;             myeval.visible = false;              if (employeetype == "2") // employee             {                 if (!request.path.tolower().contains("rateform.aspx") && !request.path.tolower().contains("myevaluation.aspx")                     && !request.path.tolower().contains("homepage.aspx"))                     response.redirect("myevaluation.aspx");                 myeval.visible = true;                  objections.visible = false;                 empevaluation.visible = false;             }             else if (employeetype == "3") // wakeel             {                 if (!request.path.tolower().contains("rateform.aspx") && !request.path.tolower().contains("objections.aspx") && !request.path.tolower().contains("userevaluation.aspx")                     && !request.path.tolower().contains("homepage.aspx") && !request.path.tolower().contains("percentages.aspx")                     && !request.path.tolower().contains("userattendance.aspx"))                     response.redirect("userevaluation.aspx");                  rates.visible = false;                 objections.visible = true;                 empevaluation.visible = true;                 attendance.visible = true;                 myeval.visible = false;                  syssettings.visible = true;                 form.visible = false;                 waitperiod.visible = false;             }             else // manager             {                 if (!request.path.tolower().contains("rateform.aspx") && !request.path.tolower().contains("myevaluation.aspx")                     && !request.path.tolower().contains("objections.aspx") && !request.path.tolower().contains("userevaluation.aspx")                     && !request.path.tolower().contains("homepage.aspx") && !request.path.tolower().contains("userattendance.aspx"))                     response.redirect("userevaluation.aspx");                 //myeval.visible = false;                  rates.visible = false;                 myeval.visible = true;                 objections.visible = true;                 empevaluation.visible = true;                 attendance.visible = true;             }              agenciesmanagers.visible = false;         }     } }

when try run on sharepoint runs , have following error

(createchildcontrole) = object reference not set instance of object

if error occurred refreshing page solving problem

any help?


Comments

Post a Comment

Popular posts from this blog

php - failed to open stream: HTTP request failed! HTTP/1.0 400 Bad Request -

this code i'm using find latitude , longitude of place: function coords($address){ echo $url="http://maps.googleapis.com/maps/api/geocode/json?address=".$address; $json = file_get_contents(urlencode($url)); $data = json_decode($json, true); print_r($data['results'][0]['geometry']['location']['lat']); print_r($data['results'][0]['geometry']['location']['lng']); } however returns warning: failed open stream: http request failed! http/1.0 400 bad request if use above code in simple procedure works fine not in function. note: have tried curl_init()... method produced same result? instead of encoding whole url encode address part. following code work fine $add='jamshoro phase 2'; $url="http://maps.googleapis.com/maps/api/geocode/json?address=".urlencode($add); $json = file_get_contents($url); $data = json_decode($json, true); print_r($data['r
Read more

java - How to filter a backspace keyboard input -

i have code gives message when key number pressed: txtvalueofclause.addeventfilter(keyevent.key_typed, new eventhandler<keyevent>() { @override public void handle(keyevent t) { char ar[] = t.getcharacter().tochararray(); char ch = ar[t.getcharacter().tochararray().length - 1]; if (!(ch >= '0' && ch <= '9')) { system.out.println("the char entered not number"); t.consume(); } } }); now if press on wrong button , press backspace remove it, error message. how can add backspace input if statement? i have found answer: txtvalueofclause.addeventfilter(keyevent.key_typed, new eventhandler<keyevent>() { @override public void handle(keyevent t) { char ar[] = t.getcharacter().tochararray(); char ch = ar[t.getcharacter().tochar
Read more

java - Show Soft Keyboard when EditText Appears -

i have code in android app, alert dialog , keyboard, , when dialog shown want keyboard appear. not , not sure why? here code: final alertdialog.builder alert = new alertdialog.builder(this); alert.settitle("title"); alert.setmessage("message"); final edittext input = new edittext(this); input.setinputtype(inputtype.type_class_number); alert.setview(input); input.setonfocuschangelistener(new view.onfocuschangelistener() { @override public void onfocuschange(view v, boolean hasfocus) { if (hasfocus) { log.i(tag, "in focus"); inputmethodmanager inputmethodmanager = (inputmethodmanager) getsystemservice(context.input_method_service); inputmethodmanager.showsoftinput(input, inputmethodmanager.show_implicit); } } }); but keyboard not appear though edit text in focus, , tell appear why, doesn't come up? thanks in advance.
Read more