c - Why is not these two return of bool equal? -

these 2 return statements not seem equal , wonder why?

bool isfound = false; return isfound; 

returns true no matter value of isfound.

bool isfound = false; return isfound ? true: false; 

returns value of isfound in case false.

i guess answer might isfound local variable , destroyed after function finished.

the return type of function const bool const doesn't seem make difference.

bool secventialsearch(int* arr, int size, int target, long* time){  struct timeval start, stop; bool isfound = false; long seconds, useconds; int* iter = arr;  gettimeofday(&start, null);  while (*iter != target && iter != &arr[size-1])     iter++;  if (*iter == target )     isfound = true;  gettimeofday(&stop, null);  seconds = stop.tv_sec - start.tv_sec; useconds = stop.tv_usec - start.tv_usec;  *time = ((seconds)*1000000 + useconds); return isfound; } 

returns true in following code in main if target not in array. altering isfound ? true: false; makes work properly.

if (secventialsearch(testarr,testarrsize,5, &test))     printf("is true."); else     printf("is false."); 

i'm assuming variable declared boolean type (bool isfound).

the expression isfound ? true : false; redundant.

it evaluate true if isfound true, or false if isfound false.

it has exact same behavior writing isfound. return isfound ? true : false; equivalent return isfound;

the same applies code like

if (isfound) {     return true; } else {     return false; } 

which same writing return isfound;

edit: said returning true:

bool isfound = false; return isfound; 

http://ideone.com/kwmxzb

double check rest of code. alone sure return false.