javascript - how to store webcam captured image in specified folder and captured image path in mysql database using php..? -


i want capture image webcam user image image stored in specified folder , captured image path store mysql using php. have problem webcam captured image path not stored in mysql database. please me...

       <script type="text/javascript" src="webcam.js"></script>      <script language="javascript">      		document.write( webcam.get_html(320, 240) );      </script>  <script language="javascript">          webcam.set_api_url( 'test.php' );      		webcam.set_quality( 90 ); // jpeg quality (1 - 100)      		webcam.set_shutter_sound( true ); // play shutter click sound      		webcam.set_hook( 'oncomplete', 'my_completion_handler' );        		function take_snapshot(){      			// take snapshot , upload server      			document.getelementbyid('upload_results').innerhtml = '<h1>uploading...</h1>';      			webcam.snap();      		}        		function my_completion_handler(msg) {      			// extract url out of php output      			if (msg.match(/(http\:\/\/\s+)/)) {      				// show jpeg image in page      				document.getelementbyid('upload_results').innerhtml ='<h1>upload successful!</h1>';      				// reset camera shot      				webcam.reset();      			}      			else {alert("php error: " + msg);      			}      		}      	</script>
-------------------------------------  ____________test.php_________________      <?php  session_start();  include 'connection.php';  $name = date('ymdhis');  $newname="images/".$name.".jpg";  $file = file_put_contents( $newname, file_get_contents('php://input') );  if (!$file) {  	print "error: failed write data $filename, check permissions\n";  	exit();  }  else  {      $sql="insert entry(images) values('$newname')";      $result=mysql_query($con,$sql)              or die("error in query");      $value=mysql_insert_id($con);      $_session["myvalue"]=$value;  }    $url = 'http://' . $_server['http_host'] . dirname($_server['request_uri']) . '/' . $newname;  print "$url\n";    ?>
      <form>     <input type=button value="configure..." onclick="webcam.configure()">      		&nbsp;&nbsp;     <input type=button value="take snapshot" onclick="take_snapshot()">     </form>      <div id="upload_results" style="background-color:#eee;"></div>

so saying works except "insert entry(images) values('$newname')"?

try echoing out full mysql error instead of brief "error in query". might table not exist, column not exist, has no auto-increment column, unnamed column has no default... anything.


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