ios - Pop to root view at midnight if app is still running -


i attempting return user first screen of application if app still , running @ midnight , things transition new day.

i using 

- (void)applicationsignificanttimechange:(uiapplication *)application

to detect change there issues...

first, there random triggers occurring @ 9:30 or 10:45 causing app kick main screen soon. understand there other factors trigger method daylight savings , messages carrier. neither of applied day triggering early.

so added in code manually check clock hour , minutes checking see if time on device between 11:58 pm , 12:02 am. 

      //get current time nsdate* = [nsdate date]; nscalendar *gregorian = [[nscalendar alloc] initwithcalendaridentifier:nsgregoriancalendar]; nsdatecomponents *datecomponents = [gregorian components:(nshourcalendarunit  | nsminutecalendarunit | nssecondcalendarunit) fromdate:now]; nsinteger hour = [datecomponents hour]; nsinteger minute = [datecomponents minute];  if ((hour>=23 && minute > 58) || (hour == 0 && minute < 2)) {    //return main screen }

this worked fine in testing manually adjusting device clock. however, left device on night, woke next morning, , never triggered.

why method finicky? , there better way handle i'm trying do.

you're complaining method being unreliable, , think of (note didn't know existence of method of 10 minutes ago), use completly different way.

from this post understand can schedule actions (through notifications) , would, instead of detect when midnight there, schedule notification @ midnight. method pops root listen specific notification, maybe check it's payload make sure of few things (that's you), , if tests passes, because assume it's been sent @ midnight, can pop.

the thing i'm unsure of advise test if notification sent when app in background/killed.

either way, can check uiapplicationstate before sending notification , react accordingly, current date , time, therefore, when user comes background or re-starts app or anything, know load.

from scratch, without brainstorming, here how understand

  • user using app => notification sent & read, foreground state => pop root

  • user has app in background => (unsure notification) => either way, set in nsuserdefaults load root vc, in -appwillenterbackground

  • user has app killed, same previous step.

and pretty got situations covered 1 method , 1 notification. have test out make sure haven't ignored important.


Comments

Post a Comment

Popular posts from this blog

php - failed to open stream: HTTP request failed! HTTP/1.0 400 Bad Request -

this code i'm using find latitude , longitude of place: function coords($address){ echo $url="http://maps.googleapis.com/maps/api/geocode/json?address=".$address; $json = file_get_contents(urlencode($url)); $data = json_decode($json, true); print_r($data['results'][0]['geometry']['location']['lat']); print_r($data['results'][0]['geometry']['location']['lng']); } however returns warning: failed open stream: http request failed! http/1.0 400 bad request if use above code in simple procedure works fine not in function. note: have tried curl_init()... method produced same result? instead of encoding whole url encode address part. following code work fine $add='jamshoro phase 2'; $url="http://maps.googleapis.com/maps/api/geocode/json?address=".urlencode($add); $json = file_get_contents($url); $data = json_decode($json, true); print_r($data['r
Read more

java - How to filter a backspace keyboard input -

i have code gives message when key number pressed: txtvalueofclause.addeventfilter(keyevent.key_typed, new eventhandler<keyevent>() { @override public void handle(keyevent t) { char ar[] = t.getcharacter().tochararray(); char ch = ar[t.getcharacter().tochararray().length - 1]; if (!(ch >= '0' && ch <= '9')) { system.out.println("the char entered not number"); t.consume(); } } }); now if press on wrong button , press backspace remove it, error message. how can add backspace input if statement? i have found answer: txtvalueofclause.addeventfilter(keyevent.key_typed, new eventhandler<keyevent>() { @override public void handle(keyevent t) { char ar[] = t.getcharacter().tochararray(); char ch = ar[t.getcharacter().tochar
Read more

java - Show Soft Keyboard when EditText Appears -

i have code in android app, alert dialog , keyboard, , when dialog shown want keyboard appear. not , not sure why? here code: final alertdialog.builder alert = new alertdialog.builder(this); alert.settitle("title"); alert.setmessage("message"); final edittext input = new edittext(this); input.setinputtype(inputtype.type_class_number); alert.setview(input); input.setonfocuschangelistener(new view.onfocuschangelistener() { @override public void onfocuschange(view v, boolean hasfocus) { if (hasfocus) { log.i(tag, "in focus"); inputmethodmanager inputmethodmanager = (inputmethodmanager) getsystemservice(context.input_method_service); inputmethodmanager.showsoftinput(input, inputmethodmanager.show_implicit); } } }); but keyboard not appear though edit text in focus, , tell appear why, doesn't come up? thanks in advance.
Read more