xml - How to get the xpath of the namespace attribute using java -


how xpath of below jaxrs:server element using java? can't solve it.

<?xml version="1.0" encoding="utf-8"?><beans xmlns="http://www.springframework.org/schema/beans" xmlns:jaxrs="http://cxf.apache.org/jaxrs" xmlns:xsi="http://www.w3.org/2001/xmlschema-instance" xsi:schemalocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.0.xsd http://cxf.apache.org/bindings/soap http://cxf.apache.org/schemas/configuration/soap.xsd http://cxf.apache.org/jaxrs http://cxf.apache.org/schemas/jaxrs.xsd">     <bean id="discoverrsbyebean" class="discovery.hello.discoverrsbye"/>     <jaxrs:server id="discoverrsbye" address="/discover_r_s_bye">         <jaxrs:servicebeans>             <ref bean="discoverrsbyebean"/>         </jaxrs:servicebeans>     </jaxrs:server>     <bean id="discoveryrshellobean" class="discovery.hello.discoveryrshello"/>     <jaxrs:server id="discoveryrshello" address="/discovery_r_s_hello">         <jaxrs:servicebeans>             <ref bean="discoveryrshellobean"/>         </jaxrs:servicebeans>     </jaxrs:server> </beans>

here code segment used 

inputstream configstream = getconfiglocation(context.getservletcontext()); documentbuilderfactory factory = documentbuilderfactory.newinstance(); documentbuilder builder = factory.newdocumentbuilder(); document doc = builder.parse(configstream); xpathfactory xpathfactory = xpathfactory.newinstance(); xpath xpath = xpathfactory.newxpath(); xpath.setnamespacecontext(new hardcodednamespaceresolver()); nodelist nodelist = (nodelist) xpath.evaluate("beans/jaxrs:server", doc, xpathconstants.nodeset);

hardcodednamespaceresolver class have namespace need use followed this article it.

i tested in .net, , figured xpath xpath, right?

"//*[namespace-uri(.)='http://cxf.apache.org/jaxrs']"

let me know if works.


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