oracle - Find records with overlapping date range in SQL -


i have following table , data:

create table customer_wer(   id_customer number,   name varchar2(10),   surname varchar2(20),   date_from date,   date_to date not null,   constraint customer_wer_pk primary key (id_customer, data_from));  insert customer_wer values (4, 'karolina', 'komuda', '01-jan-00', '31-mar-00'); insert customer_wer values (4, 'karolina', 'komuda', '01-apr-00', '30-jun-00'); insert customer_wer values (4, 'karolina', 'komuda', '15-jun-00', '30-sep-00'); insert customer_wer values (4, 'karolina', 'komuda', '01-oct-00', '31-dec-00'); insert customer_wer values (4, 'karolina', 'komuda', '01-jan-01', '31-mar-01'); insert customer_wer values (4, 'karolina', 'komuda', '01-apr-01', '30-jun-01'); insert customer_wer values (4, 'karolina', 'komuda', '01-jul-01', '5-oct-01'); insert customer_wer values (4, 'karolina', 'komuda', '01-oct-01', '31-dec-01');

i need select query find records overlapping dates. means in example above, should have 4 records in result

number  2 3 7 8

thank in advance. using oracle db.

try this:

select * t t1 join t t2 on (t1.datefrom > t2.datefrom , t1.datefrom < t2.dateto)           or (t1.dateto > t2.datefrom , t1.dateto < t2.dateto)

thank example. after modification working:

select * customer_wer k join customer_wer w on k.id_customer = w.id_customer (k.date_from > w.date_to , k.date_from < w.date_to) or (k.date_to > w.date_from , k.date_to < w.date_to);

Comments

Post a Comment

Popular posts from this blog

php - failed to open stream: HTTP request failed! HTTP/1.0 400 Bad Request -

this code i'm using find latitude , longitude of place: function coords($address){ echo $url="http://maps.googleapis.com/maps/api/geocode/json?address=".$address; $json = file_get_contents(urlencode($url)); $data = json_decode($json, true); print_r($data['results'][0]['geometry']['location']['lat']); print_r($data['results'][0]['geometry']['location']['lng']); } however returns warning: failed open stream: http request failed! http/1.0 400 bad request if use above code in simple procedure works fine not in function. note: have tried curl_init()... method produced same result? instead of encoding whole url encode address part. following code work fine $add='jamshoro phase 2'; $url="http://maps.googleapis.com/maps/api/geocode/json?address=".urlencode($add); $json = file_get_contents($url); $data = json_decode($json, true); print_r($data['r
Read more

java - How to filter a backspace keyboard input -

i have code gives message when key number pressed: txtvalueofclause.addeventfilter(keyevent.key_typed, new eventhandler<keyevent>() { @override public void handle(keyevent t) { char ar[] = t.getcharacter().tochararray(); char ch = ar[t.getcharacter().tochararray().length - 1]; if (!(ch >= '0' && ch <= '9')) { system.out.println("the char entered not number"); t.consume(); } } }); now if press on wrong button , press backspace remove it, error message. how can add backspace input if statement? i have found answer: txtvalueofclause.addeventfilter(keyevent.key_typed, new eventhandler<keyevent>() { @override public void handle(keyevent t) { char ar[] = t.getcharacter().tochararray(); char ch = ar[t.getcharacter().tochar
Read more

java - Show Soft Keyboard when EditText Appears -

i have code in android app, alert dialog , keyboard, , when dialog shown want keyboard appear. not , not sure why? here code: final alertdialog.builder alert = new alertdialog.builder(this); alert.settitle("title"); alert.setmessage("message"); final edittext input = new edittext(this); input.setinputtype(inputtype.type_class_number); alert.setview(input); input.setonfocuschangelistener(new view.onfocuschangelistener() { @override public void onfocuschange(view v, boolean hasfocus) { if (hasfocus) { log.i(tag, "in focus"); inputmethodmanager inputmethodmanager = (inputmethodmanager) getsystemservice(context.input_method_service); inputmethodmanager.showsoftinput(input, inputmethodmanager.show_implicit); } } }); but keyboard not appear though edit text in focus, , tell appear why, doesn't come up? thanks in advance.
Read more