python - Convert from bin to int/char without loosing leading "0" -


is there anyway that

>>> int('0000001',2) 1

could save leading 0s ?

what want is, huge string of bits, in 8 , 8 bits convert int, , char, , write in file. later want read file, char, use ord(), int, , bits entered, leading 0s.

you can preserve number of initial zeroes finding first index of 1 (as binary string). 

>>> s = '0000001' >>> '{}{}'.format('0'*s.index('1'),int(s,2)) '0000001' >>> s = '0000011' >>> '{}{}'.format('0'*s.index('1'),int(s,2)) '000003'

as can see, leading zeroes preserved , not number of digits.

another implementation (only zeroes included)

>>> def change(s): ...      try: ...           return '{}{}'.format('0'*s.index('1'),int(s,2)) ...      except valueerror: ...           return s ...  >>> change('000000') '000000' >>> change('000001') '000001' >>> change('000011') '00003'

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