python - Get result from mongo aggregation using pymongo 3.0 -


i know may simple question cant figure out, im getting same error again , again:

i amb using python query mongo collection , retrive value it, here is:

subquery = db.partsupp.aggregate([     {"$match": {"r_name": region }},         {"$group": {             "_id" : 0,             "minim": {"$min": "$supplycost"}             }         } ])

this query works fine , outputs: 

[{'_id': 0, 'minim': 10}]

what trying 'minim' value aggregation.

initialy wanted 'if' check if query had result, this:

if len(subselect['result']) > 0 :    minim = subquery['result'][0]['minim'] else: return subselect

but doing following error:

traceback (most recent call last): file "query2.py", line 195, in <module> pprint( list(query2('catalonia', 1, 1)) ) file "query2.py", line 72, in query2  if len(subquery['result']) > 0 : typeerror: 'commandcursor' object not subscriptable

looks result 'subselect' query not iterable or that, youo have idea on how solve ?

i using python 3.4.3 , pymongo 3.0.1

thanks in advance

pymongo 3.0.1 returns aggregation results cursor, mean can't access result subquery['result']. disable cursor , force pymongo return document {'result':{...}} instead of cursor, use this:

subquery = db.partsupp.aggregate([     {"$match": {"r_name": region }},         {"$group": {             "_id" : 0,             "minim": {"$min": "$supplycost"}             }         } ], usecursor=false)

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