xcode - Make href hypertext links in JSON strings work in iOS app -


i'm using json in app call elements database.
1 of these elements text block href links.

the json looks :

"textblock":"<a href=\"http:\/\/www.website.com\/" target=\"_blank\">link<\/a>

in app call label :

self.textlabel.text = self.item[@"textblock"]; [selftextlabel sizetofit];

result in app shows :

<a href="http://www.website.com/" target="_blank">link</a>

would possible write / strip link ?

i came across this solution strip html, works fine, links don't work, know if can keep links working.

ok, after more searching , trying, got needed.

i first tried put string in uitextview, selectable links detection. have been great if had written directly urls in text.

but again, strings receive json :

<a href="http://www.website.com/" target="_blank">link</a>

i looked @ fancy uilabels , nsdatadetector, seemed labels working still showing http:// looked not me.

so figured best way put string in uiwebview, , call (i replaced textlabel in question textview).

[self.textview loadhtmlstring:self.item[@"textblock"] baseurl:nil];

i had last issue, links opening in uiwebview instead of safari.

so added self.textview.delegate = self; in viewdidload.

and 

-(bool) webview:(uiwebview *)textview shouldstartloadwithrequest:(nsurlrequest *)inrequest navigationtype:(uiwebviewnavigationtype)intype {     if ( intype == uiwebviewnavigationtypelinkclicked ) {         [[uiapplication sharedapplication] openurl:[inrequest url]];         return no;     }      return yes; }

.h file must call uiwebviewdelegate.

and if think uiwebview default font ugly in case, did, can :

nsstring *nicertextblock = self.item[@"textblock"]; [self.textview loadhtmlstring:[nsstring stringwithformat:@"<style type='text/css'>body { font-family: helvetica; font-size: 12 } ></style>%@", nicertextblock] baseurl:nil];

hope can spare time other people.


Comments

Post a Comment

Popular posts from this blog

php - failed to open stream: HTTP request failed! HTTP/1.0 400 Bad Request -

this code i'm using find latitude , longitude of place: function coords($address){ echo $url="http://maps.googleapis.com/maps/api/geocode/json?address=".$address; $json = file_get_contents(urlencode($url)); $data = json_decode($json, true); print_r($data['results'][0]['geometry']['location']['lat']); print_r($data['results'][0]['geometry']['location']['lng']); } however returns warning: failed open stream: http request failed! http/1.0 400 bad request if use above code in simple procedure works fine not in function. note: have tried curl_init()... method produced same result? instead of encoding whole url encode address part. following code work fine $add='jamshoro phase 2'; $url="http://maps.googleapis.com/maps/api/geocode/json?address=".urlencode($add); $json = file_get_contents($url); $data = json_decode($json, true); print_r($data['r
Read more

java - How to filter a backspace keyboard input -

i have code gives message when key number pressed: txtvalueofclause.addeventfilter(keyevent.key_typed, new eventhandler<keyevent>() { @override public void handle(keyevent t) { char ar[] = t.getcharacter().tochararray(); char ch = ar[t.getcharacter().tochararray().length - 1]; if (!(ch >= '0' && ch <= '9')) { system.out.println("the char entered not number"); t.consume(); } } }); now if press on wrong button , press backspace remove it, error message. how can add backspace input if statement? i have found answer: txtvalueofclause.addeventfilter(keyevent.key_typed, new eventhandler<keyevent>() { @override public void handle(keyevent t) { char ar[] = t.getcharacter().tochararray(); char ch = ar[t.getcharacter().tochar
Read more

java - Show Soft Keyboard when EditText Appears -

i have code in android app, alert dialog , keyboard, , when dialog shown want keyboard appear. not , not sure why? here code: final alertdialog.builder alert = new alertdialog.builder(this); alert.settitle("title"); alert.setmessage("message"); final edittext input = new edittext(this); input.setinputtype(inputtype.type_class_number); alert.setview(input); input.setonfocuschangelistener(new view.onfocuschangelistener() { @override public void onfocuschange(view v, boolean hasfocus) { if (hasfocus) { log.i(tag, "in focus"); inputmethodmanager inputmethodmanager = (inputmethodmanager) getsystemservice(context.input_method_service); inputmethodmanager.showsoftinput(input, inputmethodmanager.show_implicit); } } }); but keyboard not appear though edit text in focus, , tell appear why, doesn't come up? thanks in advance.
Read more