python - Getting lat/long coordinates from identified tweets using tweepy; getting KeyError: 'coordinates' -


i'm trying lat/long coordinates identified tweets. part having trouble if decoded['coordinates']!=none: t.write(str(decoded['coordinates']['coordinates']) block. don't know if it's working or not because ~150 tweets returned coordinates [none] before error returned, believe error comes when tweet coordinates found, , returns keyerror: 'coordinates'.

the following code:

import tweepy import json htmlparser import htmlparser import os  consumer_key = '' consumer_secret = '' access_token = '' access_token_secret = ''  # listener, resposible receiving data class stdoutlistener(tweepy.streamlistener):     def on_data(self, data):         # twitter returns data in json format - need decode first         decoded = json.loads(htmlparser().unescape(data))          os.chdir('/home/scott/810py/project')         t = open('hashtaghipster.txt','a')          # also, convert utf-8 ascii ignoring bad characters sent users         #if decoded['coordinates']:          # decoded['coordinates'] returns few objects not useful,         # type , place don't want. ['coordinates'] has         # second thing called ['coordinates'] returns lat/long.         # may code correct location few , far         # between haven't been able capture one. program         # looks 'hipster' in tweet. there should stream of tweets         # in shell , everytime 1 has coordinates tehy should         # added file 'hashtaghipster.txt'. let me know think.          if decoded['coordinates']!=none:             t.write(str(decoded['coordinates']['coordinates'])) #gets [lat][long]         print '[%s] @%s: %s' % (decoded['coordinates'], decoded['user']['screen_name'], decoded['text'].encode('ascii', 'ignore'))         print ''         return true      def on_error(self, status):          print status  if __name__ == '__main__':     l = stdoutlistener()     auth = tweepy.oauthhandler(consumer_key, consumer_secret)     auth.set_access_token(access_token, access_token_secret)      print "showing new tweets #hipster:"      # there different kinds of streams: public stream, user stream, multi-user streams     # in example follow #vintage tag     # more details refer https://dev.twitter.com/docs/streaming-apis     stream = tweepy.stream(auth, l)     stream.filter(track=['hipster'])

any help? thanks.

not tweet objects contains 'coordinates' key, have check exists this:

 if decoded.get('coordinates',none) not none:    coordinates = decoded.get('coordinates','').get('coordinates','')

also, please note that:

"comparisons singletons none should done 'is' or 'is not', never equality operators."

(pep 8)


Comments

Post a Comment

Popular posts from this blog

php - failed to open stream: HTTP request failed! HTTP/1.0 400 Bad Request -

this code i'm using find latitude , longitude of place: function coords($address){ echo $url="http://maps.googleapis.com/maps/api/geocode/json?address=".$address; $json = file_get_contents(urlencode($url)); $data = json_decode($json, true); print_r($data['results'][0]['geometry']['location']['lat']); print_r($data['results'][0]['geometry']['location']['lng']); } however returns warning: failed open stream: http request failed! http/1.0 400 bad request if use above code in simple procedure works fine not in function. note: have tried curl_init()... method produced same result? instead of encoding whole url encode address part. following code work fine $add='jamshoro phase 2'; $url="http://maps.googleapis.com/maps/api/geocode/json?address=".urlencode($add); $json = file_get_contents($url); $data = json_decode($json, true); print_r($data['r
Read more

java - How to filter a backspace keyboard input -

i have code gives message when key number pressed: txtvalueofclause.addeventfilter(keyevent.key_typed, new eventhandler<keyevent>() { @override public void handle(keyevent t) { char ar[] = t.getcharacter().tochararray(); char ch = ar[t.getcharacter().tochararray().length - 1]; if (!(ch >= '0' && ch <= '9')) { system.out.println("the char entered not number"); t.consume(); } } }); now if press on wrong button , press backspace remove it, error message. how can add backspace input if statement? i have found answer: txtvalueofclause.addeventfilter(keyevent.key_typed, new eventhandler<keyevent>() { @override public void handle(keyevent t) { char ar[] = t.getcharacter().tochararray(); char ch = ar[t.getcharacter().tochar
Read more

java - Show Soft Keyboard when EditText Appears -

i have code in android app, alert dialog , keyboard, , when dialog shown want keyboard appear. not , not sure why? here code: final alertdialog.builder alert = new alertdialog.builder(this); alert.settitle("title"); alert.setmessage("message"); final edittext input = new edittext(this); input.setinputtype(inputtype.type_class_number); alert.setview(input); input.setonfocuschangelistener(new view.onfocuschangelistener() { @override public void onfocuschange(view v, boolean hasfocus) { if (hasfocus) { log.i(tag, "in focus"); inputmethodmanager inputmethodmanager = (inputmethodmanager) getsystemservice(context.input_method_service); inputmethodmanager.showsoftinput(input, inputmethodmanager.show_implicit); } } }); but keyboard not appear though edit text in focus, , tell appear why, doesn't come up? thanks in advance.
Read more