r - Creating a subset array -


all.

long story short:

i have dataset on 60000 entries.

one variable based on individual (location), 10 different categories. overall satisfaction, out of score of 1 10.

however, of categories contain either word rural, or word urban.

what compare overall mean of cases contain word rural in location variable, , cases contain word urban in location variable.

i have used work-around, create additional column in initial dataset in excel finds word rural or urban in location column , returns either rural or urban depending found, i'm sure there must way strictly using r.

is possible? thank you!

create dummy data:

set.seed(1) foo <- data.frame(   loc=sample(c(paste0("rural",letters[1:5]),paste0(letters[10:14],"urban")),     100,replace=true),   xx=rnorm(100))

now sounds want grepl() grep keywords, , by() calculate means by keyword:

> with(foo,by(xx,grepl("urban",loc),mean)) grepl("urban", loc): false [1] -0.07220176 ------------------------------- grepl("urban", loc): true [1] 0.04159463

or maybe want t-test:

> with(foo,t.test(xx~grepl("urban",loc)))          welch 2 sample t-test  data:  xx grepl("urban", loc) t = -0.60245, df = 97.076, p-value = 0.5483 alternative hypothesis: true difference in means not equal 0 95 percent confidence interval:  -0.4886860  0.2610932 sample estimates: mean in group false  mean in group true          -0.07220176          0.04159463

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