Trouble in understanding how for loops interact with arrays in c++ [homework] -


my teacher gave code user inputs number 10 digits, , each digit stored in array. need format in such way outputs each digit repeated individually. i'm trying accomplish using loop, i'm having difficulty in understanding how loop interacts array (or @ least, think that's trouble coming from). i'm @ far... can explain interaction of loop , array between lines 44 , 50 have appreciation.

#include <iostream> // provides cin, cout, endl, fixed  using namespace std;  #define digits 10 // number of base 10 digits  int main() {     // declaration section      int number,                 // number input user         digit,                  // digit of number being processed         digit_tally[digits],    // keeps track of digits seen         i;                      // general array-element counter      // initialize digit tally zeroes, indicating no repeated digits have been found      (i = 0; < digits; i++)     {         digit_tally[i] = 0;     }      // input section      cout << "enter number (any negative number exit): ";     cin >> number;      // processing section      while (number > 0)      {         digit = number % 10;          if (digit_tally[digit] == 0)         {             digit_tally[digit] = 1;          }         else if (digit_tally[digit] == 1)         {             cout << "repeated digits: ";              (digit_tally[digit] = 1; digit_tally[digit] <= 10; digit_tally[digit]++)                 cout << number << " ";         }          number = number / 10;         cout << endl;     }  } 

for reference, output should this:

enter number (any negative number exit): 64246

repeated digits: 4 6

as have got logic of storing number of occurrences in index. can proceed approach , once finish lopping through entire number, have loop prints index has more 1 occurrence.

while (number > 0)  {         digit = number % 10;         digit_tally[digit -1] += 1;         number = number / 10;         cout << endl;  }   ( int = 0; < 10; ++i)  {     if (digit_tally[i] > 1)     {        std::cout << + 1 << " ";     }  } 

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